15y^2-24y-12=0

Solution for 15y^2-24y-12=0 equation:

15y^2-24y-12=0

a = 15; b = -24; c = -12;
Δ = b2-4ac
Δ = -242-4·15·(-12)
Δ = 1296
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1296}=36$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-24)-36}{2*15}=\frac{-12}{30}
=-2/5
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-24)+36}{2*15}=\frac{60}{30}
=2
$